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x86/fineibt: Poison ENDBR at +0
Alyssa noticed that when building the kernel with CFI_CLANG+IBT and booting on IBT enabled hardware to obtain FineIBT, the indirect functions look like: __cfi_foo: endbr64 subl $hash, %r10d jz 1f ud2 nop 1: foo: endbr64 This is because the compiler generates code for kCFI+IBT. In that case the caller does the hash check and will jump to +0, so there must be an ENDBR there. The compiler doesn't know about FineIBT at all; also it is possible to actually use kCFI+IBT when booting with 'cfi=kcfi' on IBT enabled hardware. Having this second ENDBR however makes it possible to elide the CFI check. Therefore, we should poison this second ENDBR when switching to FineIBT mode. Fixes: 931ab63664f0 ("x86/ibt: Implement FineIBT") Reported-by: "Milburn, Alyssa" <alyssa.milburn@intel.com> Signed-off-by: Peter Zijlstra (Intel) <peterz@infradead.org> Reviewed-by: Kees Cook <keescook@chromium.org> Reviewed-by: Sami Tolvanen <samitolvanen@google.com> Link: https://lore.kernel.org/r/20230615193722.194131053@infradead.org
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@ -1068,6 +1068,17 @@ static int cfi_rewrite_preamble(s32 *start, s32 *end)
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return 0;
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}
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static void cfi_rewrite_endbr(s32 *start, s32 *end)
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{
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s32 *s;
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for (s = start; s < end; s++) {
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void *addr = (void *)s + *s;
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poison_endbr(addr+16, false);
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}
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}
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/* .retpoline_sites */
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static int cfi_rand_callers(s32 *start, s32 *end)
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{
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@ -1162,14 +1173,19 @@ static void __apply_fineibt(s32 *start_retpoline, s32 *end_retpoline,
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return;
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case CFI_FINEIBT:
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/* place the FineIBT preamble at func()-16 */
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ret = cfi_rewrite_preamble(start_cfi, end_cfi);
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if (ret)
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goto err;
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/* rewrite the callers to target func()-16 */
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ret = cfi_rewrite_callers(start_retpoline, end_retpoline);
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if (ret)
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goto err;
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/* now that nobody targets func()+0, remove ENDBR there */
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cfi_rewrite_endbr(start_cfi, end_cfi);
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if (builtin)
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pr_info("Using FineIBT CFI\n");
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return;
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