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leds: multicolor: Use rounded division when calculating color components
Given channel intensity, LED brightness and max LED brightness, the multicolor LED framework helper led_mc_calc_color_components() computes the color channel brightness as chan_brightness = brightness * chan_intensity / max_brightness Consider the situation when (brightness, intensity, max_brightness) is for example (16, 15, 255), then chan_brightness is computed to 0 although the fractional divison would give 0.94, which should be rounded to 1. Use DIV_ROUND_CLOSEST here for the division to give more realistic component computation: chan_brightness = DIV_ROUND_CLOSEST(brightness * chan_intensity, max_brightness) Fixes: 55d5d3b46b08 ("leds: multicolor: Introduce a multicolor class definition") Signed-off-by: Marek Behún <kabel@kernel.org> Link: https://lore.kernel.org/r/20230801124931.8661-1-kabel@kernel.org Signed-off-by: Lee Jones <lee@kernel.org>
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@ -6,6 +6,7 @@
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#include <linux/device.h>
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#include <linux/init.h>
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#include <linux/led-class-multicolor.h>
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#include <linux/math.h>
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#include <linux/module.h>
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#include <linux/slab.h>
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#include <linux/uaccess.h>
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@ -19,9 +20,10 @@ int led_mc_calc_color_components(struct led_classdev_mc *mcled_cdev,
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int i;
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for (i = 0; i < mcled_cdev->num_colors; i++)
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mcled_cdev->subled_info[i].brightness = brightness *
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mcled_cdev->subled_info[i].intensity /
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led_cdev->max_brightness;
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mcled_cdev->subled_info[i].brightness =
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DIV_ROUND_CLOSEST(brightness *
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mcled_cdev->subled_info[i].intensity,
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led_cdev->max_brightness);
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return 0;
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}
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