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locking/lockdep: Remove redundant argument in check_deadlock

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In check_deadlock(), the third argument read comes from the second
argument hlock so that it can be removed. No functional change.

Signed-off-by: Yuyang Du <duyuyang@gmail.com>
Signed-off-by: Peter Zijlstra (Intel) <peterz@infradead.org>
Cc: Linus Torvalds <torvalds@linux-foundation.org>
Cc: Peter Zijlstra <peterz@infradead.org>
Cc: Thomas Gleixner <tglx@linutronix.de>
Cc: bvanassche@acm.org
Cc: frederic@kernel.org
Cc: ming.lei@redhat.com
Cc: will.deacon@arm.com
Link: https://lkml.kernel.org/r/20190506081939.74287-18-duyuyang@gmail.com
Signed-off-by: Ingo Molnar <mingo@kernel.org>
This commit is contained in:
Yuyang Du 2019-05-06 16:19:33 +08:00 committed by Ingo Molnar
parent 1ac4ba5ed0
commit 4609c4f963
1 changed files with 3 additions and 3 deletions
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6
kernel/locking/lockdep.c
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@ -2246,7 +2246,7 @@ print_deadlock_bug(struct task_struct *curr, struct held_lock *prev,
* Returns: 0 on deadlock detected, 1 on OK, 2 on recursive read
*/
static int
check_deadlock(struct task_struct *curr, struct held_lock *next, int read)
check_deadlock(struct task_struct *curr, struct held_lock *next)
{
struct held_lock *prev;
struct held_lock *nest = NULL;
@ -2265,7 +2265,7 @@ check_deadlock(struct task_struct *curr, struct held_lock *next, int read)
* Allow read-after-read recursion of the same
* lock class (i.e. read_lock(lock)+read_lock(lock)):
*/
if ((read == 2) && prev->read)
if ((next->read == 2) && prev->read)
return 2;
/*
@ -2839,7 +2839,7 @@ static int validate_chain(struct task_struct *curr,
* The simple case: does the current hold the same lock
* already?
*/
int ret = check_deadlock(curr, hlock, hlock->read);
int ret = check_deadlock(curr, hlock);
if (!ret)
return 0;