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ide: Handle irq disabling consistently
ide_timer_expiry() disables interrupt at function entry when acquiring hwif->lock. Before disabling the device interrupt it unlocks hwif->lock, but interrupts stay disabled. After the call to disable_irq() interrupts are disabled again, which is a pointless exercise. After the device irq handler has been invoked with interrupts disabled, hwif->lock is acquired again with spin_lock_irq() because the device irq handler might have reenabled interrupts. This is not documented and confusing for the casual reader. Remove the redundant local_irq_disable() and add a comment which explains why hwif->lock has to be reacquired with spin_lock_irq(). Signed-off-by: Sebastian Andrzej Siewior <bigeasy@linutronix.de> Acked-by: David S. Miller <davem@davemloft.net> Signed-off-by: David S. Miller <davem@davemloft.net>
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@ -659,8 +659,7 @@ void ide_timer_expiry (struct timer_list *t)
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spin_unlock(&hwif->lock);
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/* disable_irq_nosync ?? */
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disable_irq(hwif->irq);
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/* local CPU only, as if we were handling an interrupt */
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local_irq_disable();
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if (hwif->polling) {
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startstop = handler(drive);
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} else if (drive_is_ready(drive)) {
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@ -679,6 +678,7 @@ void ide_timer_expiry (struct timer_list *t)
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startstop = ide_error(drive, "irq timeout",
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hwif->tp_ops->read_status(hwif));
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}
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/* Disable interrupts again, `handler' might have enabled it */
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spin_lock_irq(&hwif->lock);
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enable_irq(hwif->irq);
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if (startstop == ide_stopped && hwif->polling == 0) {
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