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sched/debug: Fix task state recording/printout
The recent conversion of the task state recording to use task_state_index() broke the sched_switch tracepoint task state output. task_state_index() returns surprisingly an index (0-7) which is then printed with __print_flags() applying bitmasks. Not really working and resulting in weird states like 'prev_state=t' instead of 'prev_state=I'. Use TASK_REPORT_MAX instead of TASK_STATE_MAX to report preemption. Build a bitmask from the return value of task_state_index() and store it in entry->prev_state, which makes __print_flags() work as expected. Signed-off-by: Thomas Gleixner <tglx@linutronix.de> Cc: Linus Torvalds <torvalds@linux-foundation.org> Cc: Paul E. McKenney <paulmck@linux.vnet.ibm.com> Cc: Peter Zijlstra <peterz@infradead.org> Cc: Steven Rostedt <rostedt@goodmis.org> Cc: stable@vger.kernel.org Fixes: efb40f588b43 ("sched/tracing: Fix trace_sched_switch task-state printing") Link: http://lkml.kernel.org/r/alpine.DEB.2.20.1711221304180.1751@nanos Signed-off-by: Ingo Molnar <mingo@kernel.org>
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@ -116,9 +116,9 @@ static inline long __trace_sched_switch_state(bool preempt, struct task_struct *
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* RUNNING (we will not have dequeued if state != RUNNING).
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*/
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if (preempt)
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return TASK_STATE_MAX;
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return TASK_REPORT_MAX;
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return task_state_index(p);
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return 1 << task_state_index(p);
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}
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#endif /* CREATE_TRACE_POINTS */
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@ -164,7 +164,7 @@ TRACE_EVENT(sched_switch,
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{ 0x40, "P" }, { 0x80, "I" }) :
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"R",
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__entry->prev_state & TASK_STATE_MAX ? "+" : "",
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__entry->prev_state & TASK_REPORT_MAX ? "+" : "",
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__entry->next_comm, __entry->next_pid, __entry->next_prio)
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);
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