watchdog: rza_wdt: don't print out if registering watchdog fails

The core will do this already.

Signed-off-by: Wolfram Sang <wsa+renesas@sang-engineering.com>
Reviewed-by: Wim Van Sebroeck <wim@linux-watchdog.org>
Link: https://lore.kernel.org/r/20241004200314.5459-9-wsa+renesas@sang-engineering.com
Signed-off-by: Guenter Roeck <linux@roeck-us.net>
Signed-off-by: Wim Van Sebroeck <wim@linux-watchdog.org>
This commit is contained in:
Wolfram Sang 2024-10-04 22:03:11 +02:00 committed by Wim Van Sebroeck
parent 844f8dff29
commit 74ccee5e6c

View File

@ -169,7 +169,6 @@ static int rza_wdt_probe(struct platform_device *pdev)
struct device *dev = &pdev->dev;
struct rza_wdt *priv;
unsigned long rate;
int ret;
priv = devm_kzalloc(dev, sizeof(*priv), GFP_KERNEL);
if (!priv)
@ -218,11 +217,7 @@ static int rza_wdt_probe(struct platform_device *pdev)
watchdog_init_timeout(&priv->wdev, 0, dev);
watchdog_set_drvdata(&priv->wdev, priv);
ret = devm_watchdog_register_device(dev, &priv->wdev);
if (ret)
dev_err(dev, "Cannot register watchdog device\n");
return ret;
return devm_watchdog_register_device(dev, &priv->wdev);
}
static const struct of_device_id rza_wdt_of_match[] = {