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i915: make inject_virtual_interrupt() void
The single caller of inject_virtual_interrupt() ignores the return value anyway. This allows us to simplify eventfd_signal() in follow-up patches. Link: https://lore.kernel.org/r/20231122-vfs-eventfd-signal-v2-1-bd549b14ce0c@kernel.org Reviewed-by: Jan Kara <jack@suse.cz> Reviewed-by: Zhenyu Wang <zhenyuw@linux.intel.com> Reviewed-by: Jens Axboe <axboe@kernel.dk> Signed-off-by: Christian Brauner <brauner@kernel.org>
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@ -422,7 +422,7 @@ static void init_irq_map(struct intel_gvt_irq *irq)
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#define MSI_CAP_DATA(offset) (offset + 8)
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#define MSI_CAP_EN 0x1
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static int inject_virtual_interrupt(struct intel_vgpu *vgpu)
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static void inject_virtual_interrupt(struct intel_vgpu *vgpu)
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{
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unsigned long offset = vgpu->gvt->device_info.msi_cap_offset;
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u16 control, data;
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@ -434,10 +434,10 @@ static int inject_virtual_interrupt(struct intel_vgpu *vgpu)
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/* Do not generate MSI if MSIEN is disabled */
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if (!(control & MSI_CAP_EN))
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return 0;
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return;
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if (WARN(control & GENMASK(15, 1), "only support one MSI format\n"))
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return -EINVAL;
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return;
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trace_inject_msi(vgpu->id, addr, data);
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@ -451,10 +451,9 @@ static int inject_virtual_interrupt(struct intel_vgpu *vgpu)
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* returned and don't inject interrupt into guest.
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*/
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if (!test_bit(INTEL_VGPU_STATUS_ATTACHED, vgpu->status))
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return -ESRCH;
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if (vgpu->msi_trigger && eventfd_signal(vgpu->msi_trigger, 1) != 1)
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return -EFAULT;
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return 0;
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return;
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if (vgpu->msi_trigger)
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eventfd_signal(vgpu->msi_trigger, 1);
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}
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static void propagate_event(struct intel_gvt_irq *irq,
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