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maple_tree: simplify mas_push_node()
When count is not 0, we know head is valid. So we can put the assignment in if (count) instead of checking the head pointer again. Also count represents current total, we can assign the new total by increasing the count by one. Link: https://lkml.kernel.org/r/20241015120746.15850-4-richard.weiyang@gmail.com Signed-off-by: Wei Yang <richard.weiyang@gmail.com> Reviewed-by: Liam R. Howlett <Liam.Howlett@Oracle.com> Cc: Sidhartha Kumar <sidhartha.kumar@oracle.com> Cc: Lorenzo Stoakes <lorenzo.stoakes@oracle.com> Signed-off-by: Andrew Morton <akpm@linux-foundation.org>
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@ -1207,19 +1207,17 @@ static inline void mas_push_node(struct ma_state *mas, struct maple_node *used)
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reuse->request_count = 0;
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reuse->node_count = 0;
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if (count && (head->node_count < MAPLE_ALLOC_SLOTS)) {
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head->slot[head->node_count++] = reuse;
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head->total++;
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goto done;
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}
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reuse->total = 1;
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if ((head) && !((unsigned long)head & 0x1)) {
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if (count) {
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if (head->node_count < MAPLE_ALLOC_SLOTS) {
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head->slot[head->node_count++] = reuse;
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head->total++;
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goto done;
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}
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reuse->slot[0] = head;
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reuse->node_count = 1;
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reuse->total += head->total;
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}
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reuse->total = count + 1;
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mas->alloc = reuse;
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done:
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if (requested > 1)
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