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eCryptfs: Use DEFINE_MUTEX() for mutex lock
mutex lock can be initialized automatically with DEFINE_MUTEX() rather than explicitly calling mutex_init(). Reported-by: Hulk Robot <hulkci@huawei.com> Signed-off-by: Ye Bin <yebin10@huawei.com> Signed-off-by: Tyler Hicks <code@tyhicks.com>
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@ -14,10 +14,10 @@
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static LIST_HEAD(ecryptfs_msg_ctx_free_list);
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static LIST_HEAD(ecryptfs_msg_ctx_alloc_list);
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static struct mutex ecryptfs_msg_ctx_lists_mux;
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static DEFINE_MUTEX(ecryptfs_msg_ctx_lists_mux);
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static struct hlist_head *ecryptfs_daemon_hash;
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struct mutex ecryptfs_daemon_hash_mux;
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DEFINE_MUTEX(ecryptfs_daemon_hash_mux);
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static int ecryptfs_hash_bits;
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#define ecryptfs_current_euid_hash(uid) \
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hash_long((unsigned long)from_kuid(&init_user_ns, current_euid()), ecryptfs_hash_bits)
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@ -361,7 +361,6 @@ int __init ecryptfs_init_messaging(void)
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"too large, defaulting to [%d] users\n", __func__,
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ecryptfs_number_of_users);
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}
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mutex_init(&ecryptfs_daemon_hash_mux);
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mutex_lock(&ecryptfs_daemon_hash_mux);
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ecryptfs_hash_bits = 1;
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while (ecryptfs_number_of_users >> ecryptfs_hash_bits)
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@ -385,7 +384,6 @@ int __init ecryptfs_init_messaging(void)
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rc = -ENOMEM;
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goto out;
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}
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mutex_init(&ecryptfs_msg_ctx_lists_mux);
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mutex_lock(&ecryptfs_msg_ctx_lists_mux);
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ecryptfs_msg_counter = 0;
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for (i = 0; i < ecryptfs_message_buf_len; i++) {
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