blk-iocost: simplify ioc_name

Just directly dereference the disk name instead of going through multiple
hoops to find the same value.

Signed-off-by: Christoph Hellwig <hch@lst.de>
Reviewed-by: Andreas Herrmann <aherrmann@suse.de>
Acked-by: Tejun Heo <tj@kernel.org>
Link: https://lore.kernel.org/r/20220921180501.1539876-10-hch@lst.de
Signed-off-by: Jens Axboe <axboe@kernel.dk>
This commit is contained in:
Christoph Hellwig 2022-09-21 20:04:53 +02:00 committed by Jens Axboe
parent 16fac1b591
commit 9df3e65139

View File

@ -664,17 +664,13 @@ static struct ioc *q_to_ioc(struct request_queue *q)
return rqos_to_ioc(rq_qos_id(q, RQ_QOS_COST));
}
static const char *q_name(struct request_queue *q)
{
if (blk_queue_registered(q))
return kobject_name(q->kobj.parent);
else
return "<unknown>";
}
static const char __maybe_unused *ioc_name(struct ioc *ioc)
{
return q_name(ioc->rqos.q);
struct gendisk *disk = ioc->rqos.q->disk;
if (!disk)
return "<unknown>";
return disk->disk_name;
}
static struct ioc_gq *pd_to_iocg(struct blkg_policy_data *pd)