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btrfs: remove redundant initializations for struct btrfs_tree_parent_check

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It's pointless to initialize the has_first_key field of the stack local
btrfs_tree_parent_check structure at btrfs_tree_parent_check() and at
btrfs_qgroup_trace_subtree() since all fields not explicitly initialized
are zeroed out. In the case of the first function it's a bit odd because
we are assigning 0 and the field is of type bool, however not incorrect
since a 0 is converted to false.

Just remove the explicit initializations due to their redundancy.

Signed-off-by: Filipe Manana <fdmanana@suse.com>
Reviewed-by: David Sterba <dsterba@suse.com>
Signed-off-by: David Sterba <dsterba@suse.com>
This commit is contained in:
Filipe Manana 2024-10-16 11:09:26 +01:00 committed by David Sterba
parent c88ebf1db5
commit b8e63ea405
2 changed files with 0 additions and 2 deletions
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1
fs/btrfs/extent_io.c
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@ -4286,7 +4286,6 @@ void btrfs_readahead_tree_block(struct btrfs_fs_info *fs_info,
u64 bytenr, u64 owner_root, u64 gen, int level)
{
struct btrfs_tree_parent_check check = {
.has_first_key = 0,
.level = level,
.transid = gen
};

1
fs/btrfs/qgroup.c
View File

@ -2648,7 +2648,6 @@ int btrfs_qgroup_trace_subtree(struct btrfs_trans_handle *trans,
if (!extent_buffer_uptodate(root_eb)) {
struct btrfs_tree_parent_check check = {
.has_first_key = false,
.transid = root_gen,
.level = root_level
};