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Currently, the whole indexes will only be compacted 4B if compacted_4b_initial > totalidx. So, the calculated compacted_2b is worthless for that case. It may waste CPU resources. No need to update compacted_4b_initial as mkfs since it's used to fulfill the alignment of the 1st compacted_2b pack and would handle the case above. We also need to clarify compacted_4b_end here. It's used for the last lclusters which aren't fitted in the previous compacted_2b packs. Some messages are from Xiang. Link: https://lore.kernel.org/r/20210914035915.1190-1-zbestahu@gmail.com Signed-off-by: Yue Hu <huyue2@yulong.com> Reviewed-by: Gao Xiang <hsiangkao@linux.alibaba.com> Reviewed-by: Chao Yu <chao@kernel.org> [ Gao Xiang: it's enough to use "compacted_4b_initial < totalidx". ] Signed-off-by: Gao Xiang <hsiangkao@linux.alibaba.com>