std::chrono::time_point<Clock,Duration>::time_since_epoch

 

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std::chrono::time_point

成员函数

time_point::time_point

time_point::time_since_epoch

time_point::operator+=time_point::operator-=

time_point::operator++time_point::operator-- (C++20)(C++20)

time_point::min

time_point::max

非成员函数

operator+operator-

operator==operator!=operator<operator<=operator>operator>=operator<=> (C++20 前)(C++20)

time_point_cast

floor (C++17)

ceil (C++17)

round (C++17)

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common_type

hash<std::chrono::time_point> (C++26)

 

duration time_since_epoch() const;		(C++11 起) (C++14 起为 constexpr)

返回表示 *this 与 clock 的纪元间的时间量的 duration。

参数

（无）

返回值

此 time_point 与 clock 的纪元间的时间量。

示例

运行此代码

#include <chrono>
#include <ctime>
#include <iostream>
 
int main()
{
    const auto p0 = std::chrono::time_point<std::chrono::system_clock>{};
    const auto p1 = std::chrono::system_clock::now();
    const auto p2 = p1 - std::chrono::hours(24);
 
    std::time_t epoch_time = std::chrono::system_clock::to_time_t(p0);
    std::cout << "纪元: " << std::ctime(&epoch_time);
    std::time_t today_time = std::chrono::system_clock::to_time_t(p1);
    std::cout << "今天: " << std::ctime(&today_time);
 
    std::cout << "纪元起小时数: "
              << std::chrono::duration_cast<std::chrono::hours>(
                     p1.time_since_epoch()).count() 
              << '\n';
    std::cout << "昨天，纪元起小时数: "
              << std::chrono::duration_cast<std::chrono::hours>(
                     p2.time_since_epoch()).count() 
              << '\n';
}

可能的输出：

纪元: Thu Jan  1 00:00:00 1970
今天: Fri Jun 30 10:44:11 2017
纪元起小时数: 416338
昨天，纪元起小时数: 416314