std::chrono::year::operator+, std::chrono::year::operator-

来自cppreference.com
< cpp‎ | chrono‎ | year
 
 
 
 
constexpr std::chrono::year operator+() noexcept;
(1) (C++20 起)
constexpr std::chrono::year operator-() noexcept;
(2) (C++20 起)

应用一元运算符到年份值。

1) 返回 *this 的副本。
2) 返回年份值为 *this 的年份值相反数的 year

返回值

1) *this
2) std::chrono::year(-int(*this))

示例

#include <chrono>
#include <iostream>
 
int main()
{
    constexpr std::chrono::year y{2020};
    constexpr auto ny = -y;
    std::cout << "年份 " << (int)y << " 取负值为 " << (int)ny << '\n';
}

输出:

年份 2020 取负值为 -2020