std::operator<<(std::basic_stacktrace)

 

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std::basic_stacktrace

成员函数

basic_stacktrace::basic_stacktrace (C++23)

basic_stacktrace::~basic_stacktrace (C++23)

basic_stacktrace::operator= (C++23)

basic_stacktrace::current (C++23)

basic_stacktrace::get_allocator (C++23)

迭代器

basic_stacktrace::beginbasic_stacktrace::cbegin (C++23)(C++23)

basic_stacktrace::endbasic_stacktrace::cend (C++23)(C++23)

basic_stacktrace::rbeginbasic_stacktrace::crbegin (C++23)(C++23)

basic_stacktrace::rendbasic_stacktrace::crend (C++23)(C++23)

容量

basic_stacktrace::empty (C++23)

basic_stacktrace::size (C++23)

basic_stacktrace::max_size (C++23)

元素访问

basic_stacktrace::operator[] (C++23)

basic_stacktrace::at (C++23)

修改器

basic_stacktrace::swap (C++23)

非成员函数

operator== operator<=> (C++23)(C++23)

std::swap (C++23)

to_string (C++23)

operator<< (C++23)

辅助类

hash<basic_stacktrace> (C++23)

 

定义于头文件 <stacktrace>
template< class CharT, class Traits, class Allocator > std::basic_ostream<CharT, Traits>& operator<<( std::basic_ostream<CharT, Traits>& os,                                                const std::basic_stacktrace<Allocator>& st );		(C++23 起)

插入 st 的描述到输出流 os 中。等价于 return os << std::to_string(st); 。

参数

os	-	输出流
st	-	要插入其描述的 basic_stacktrace

返回值

os 。

异常

可能抛出实现定义的异常。

注解

由于 std::string 只能由 std::ostream 输出（例如不能由 std::wostream ），这等效地要求 os 的类型为 std::ostream& 。

示例

运行此代码

#include <stacktrace>
#include <iostream>
 
int main()
{
    std::cout << "The stacktrace obtained in the main function:\n";
    std::cout << std::stacktrace::current() << '\n';
    []{
        std::cout << "The stacktrace obtained in a nested lambda:\n";
        std::cout << std::stacktrace::current() << '\n';
    }();
}

可能的输出：

The stacktrace obtained in the main function:
 0# 0x0000000000402E7B in ./prog.exe
 1# __libc_start_main in /lib/x86_64-linux-gnu/libc.so.6
 2# 0x0000000000402CD9 in ./prog.exe
 
The stacktrace obtained in a nested lambda:
 0# 0x0000000000402DDA in ./prog.exe
 1# 0x0000000000402EB2 in ./prog.exe
 2# __libc_start_main in /lib/x86_64-linux-gnu/libc.so.6
 3# 0x0000000000402CD9 in ./prog.exe

参阅

operator<< (C++23)

进行 stacktrace_entry 的流输出 (函数模板)