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sched, trace: Fix prev_state output in sched_switch tracepoint
commit 3f5fe9fef5b2 ("sched/debug: Fix task state recording/printout") tried to fix the problem introduced by a previous commit efb40f588b43 ("sched/tracing: Fix trace_sched_switch task-state printing"). However the prev_state output in sched_switch is still broken. task_state_index() uses fls() which considers the LSB as 1. Left shifting 1 by this value gives an incorrect mapping to the task state. Fix this by decrementing the value returned by __get_task_state() before shifting. Link: http://lkml.kernel.org/r/1540882473-1103-1-git-send-email-pkondeti@codeaurora.org Cc: stable@vger.kernel.org Fixes: 3f5fe9fef5b2 ("sched/debug: Fix task state recording/printout") Signed-off-by: Pavankumar Kondeti <pkondeti@codeaurora.org> Signed-off-by: Steven Rostedt (VMware) <rostedt@goodmis.org>
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@ -107,6 +107,8 @@ DEFINE_EVENT(sched_wakeup_template, sched_wakeup_new,
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#ifdef CREATE_TRACE_POINTS
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static inline long __trace_sched_switch_state(bool preempt, struct task_struct *p)
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{
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unsigned int state;
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#ifdef CONFIG_SCHED_DEBUG
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BUG_ON(p != current);
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#endif /* CONFIG_SCHED_DEBUG */
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@ -118,7 +120,15 @@ static inline long __trace_sched_switch_state(bool preempt, struct task_struct *
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if (preempt)
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return TASK_REPORT_MAX;
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return 1 << task_state_index(p);
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/*
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* task_state_index() uses fls() and returns a value from 0-8 range.
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* Decrement it by 1 (except TASK_RUNNING state i.e 0) before using
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* it for left shift operation to get the correct task->state
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* mapping.
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*/
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state = task_state_index(p);
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return state ? (1 << (state - 1)) : state;
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}
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#endif /* CREATE_TRACE_POINTS */
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