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sched: fix incorrect assumption that cpu 0 exists
This patch: commit 9b5b77512dce239fa168183fa71896712232e95a Author: Srivatsa Vaddagiri <vatsa@linux.vnet.ibm.com> Date: Mon Oct 15 17:00:09 2007 +0200 sched: clean up code under CONFIG_FAIR_GROUP_SCHED Introduced an assumption of the existence of CPU0 via this line cfs_rq = tg->cfs_rq[0]; If you have no CPU0, that will be NULL. The fix seems to be just to take whatever cfs_rq queue comes out of the for_each_possible_cpu() loop, since they're all equally good for the destruction operation. Signed-off-by: James Bottomley <James.Bottomley@SteelEye.com> Signed-off-by: Ingo Molnar <mingo@elte.hu>
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@ -7041,7 +7041,7 @@ static void free_sched_group(struct rcu_head *rhp)
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/* Destroy runqueue etc associated with a task group */
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void sched_destroy_group(struct task_group *tg)
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{
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struct cfs_rq *cfs_rq;
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struct cfs_rq *cfs_rq = NULL;
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int i;
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for_each_possible_cpu(i) {
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@ -7049,7 +7049,7 @@ void sched_destroy_group(struct task_group *tg)
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list_del_rcu(&cfs_rq->leaf_cfs_rq_list);
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}
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cfs_rq = tg->cfs_rq[0];
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BUG_ON(!cfs_rq);
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/* wait for possible concurrent references to cfs_rqs complete */
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call_rcu(&cfs_rq->rcu, free_sched_group);
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