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file: flush delayed work in delayed fput()
The fput() of file rcS might not have completed causing issues when executing the file. rcS is opened in do_populate_rootfs before executed. At the end of do_populate_rootfs() flush_delayed_fput() is called. Now do_populate_rootfs() assumes that all fput()s caused by do_populate_rootfs() have completed. But flush_delayed_fput() can only ensure that fput() on the current delayed_fput_list has finished. Any file that has been removed from delayed_fput_list asynchronously in the meantime might not have completed causing the exec to fail. do_populate_rootfs delayed_fput_list delayed_fput execve fput() a fput() a->b fput() a->b->rcS __fput(a) fput() c fput() c->d __fput(b) flush_delayed_fput __fput(c) __fput(d) __fput(b) __fput(b) execve(rcS) Ensure that all delayed work is done by calling flush_delayed_work() in flush_delayed_fput() explicitly. Signed-off-by: Chen Lin <chen.lin5@zte.com.cn> Signed-off-by: Shao Mingyin <shao.mingyin@zte.com.cn> Link: https://lore.kernel.org/r/20241023135850067m3w2R0UXESiVCYz_wdAoT@zte.com.cn Cc: Yang Yang <yang.yang29@zte.com.cn> Cc: Yang Tao <yang.tao172@zte.com.cn> Cc: Xu Xin <xu.xin16@zte.com.cn> [brauner: rewrite commit message] Signed-off-by: Christian Brauner <brauner@kernel.org>
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@ -478,6 +478,8 @@ static void ____fput(struct callback_head *work)
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__fput(container_of(work, struct file, f_task_work));
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}
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static DECLARE_DELAYED_WORK(delayed_fput_work, delayed_fput);
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/*
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* If kernel thread really needs to have the final fput() it has done
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* to complete, call this. The only user right now is the boot - we
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@ -491,11 +493,10 @@ static void ____fput(struct callback_head *work)
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void flush_delayed_fput(void)
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{
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delayed_fput(NULL);
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flush_delayed_work(&delayed_fput_work);
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}
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EXPORT_SYMBOL_GPL(flush_delayed_fput);
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static DECLARE_DELAYED_WORK(delayed_fput_work, delayed_fput);
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void fput(struct file *file)
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{
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if (file_ref_put(&file->f_ref)) {
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