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virtiofs: drop __exit from virtio_fs_sysfs_exit()

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virtio_fs_sysfs_exit() is called by:
- static int __init virtio_fs_init(void)
- static void __exit virtio_fs_exit(void)

Remove __exit from virtio_fs_sysfs_exit() since virtio_fs_init() is not
an __exit function.

Reported-by: kernel test robot <lkp@intel.com>
Closes: https://lore.kernel.org/oe-kbuild-all/202402270649.GYjNX0yw-lkp@intel.com/
Signed-off-by: Stefan Hajnoczi <stefanha@redhat.com>
Reviewed-by: Randy Dunlap <rdunlap@infradead.org>
Tested-by: Randy Dunlap <rdunlap@infradead.org> # build-tested
Signed-off-by: Miklos Szeredi <mszeredi@redhat.com>
This commit is contained in:
Stefan Hajnoczi 2024-02-27 10:57:56 -05:00 committed by Miklos Szeredi
parent fda0b98ef0
commit d30ff89870
1 changed files with 1 additions and 1 deletions
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2
fs/fuse/virtio_fs.c
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@ -1588,7 +1588,7 @@ static int __init virtio_fs_sysfs_init(void)
return 0;
}
static void __exit virtio_fs_sysfs_exit(void)
static void virtio_fs_sysfs_exit(void)
{
kset_unregister(virtio_fs_kset);
virtio_fs_kset = NULL;