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By associative and commutative laws, the result of the two 'audited' is zero. Take the second 'audited' as an example: 1) audited = requested & avd->auditallow; 2) audited &= ~requested; ==> audited = ~requested & (requested & avd->auditallow); ==> audited = (~requested & requested) & avd->auditallow; ==> audited = 0 & avd->auditallow; ==> audited = 0; In fact, it is more readable to directly write zero. The value of the first 'audited' is 0 because AUDIT is not allowed. The second 'audited' is zero because there is no AUDITALLOW permission. Signed-off-by: Zhen Lei <thunder.leizhen@huawei.com> Signed-off-by: Paul Moore <paul@paul-moore.com> |
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